1 条题解

  • 0
    @ 2023-7-27 15:43:39

    一本通例题

    #include <bits/stdc++.h>
    using namespace std;
    
    double fn(double x,double a,double b,double c,double d);
    
    int main()
    {
        double a,b,c,d;
        cin >>a>>b>>c>>d;
        for(int i=-10000; i<=10000; i++){
            double x1=(i-0.05)/100;
            double x2=(i+0.05)/100;
            if(fn(x1,a,b,c,d)*fn(x2,a,b,c,d)<0 || fn(x1,a,b,c,d)==0){
                printf("%.2f",double(i)/100);
                cout <<" ";
            }
        }
    
    
    
        return 0;
    }
        double fn(double x,double a,double b,double c,double d){
            double f;
            f=a*x*x*x+b*x*x+c*x+d;
            return f;
        }
    
    
    • 1

    信息

    ID
    237
    时间
    1000ms
    内存
    64MiB
    难度
    9
    标签
    递交数
    14
    已通过
    4
    上传者