3 条题解
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1
s=input() a=[0]*26 for i in s: if "A"<=i<="Z": a[ord(i)-ord("A")]+=1 elif "a"<=i<="z": n=ord(i)-ord("a") a[n]=a[n]+1 imax=a[0] for i in range(1,26): if imax<a[i]: imax=a[i] s1="";s2="" for i in range(len(a)): if imax==a[i]: s1=s1+" "+chr(ord("A")+i) elif a[i]==0: s2=s2+" "+chr(ord("A")+i) print(s1[1:]) print(imax) print(s2[1:])
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1
s = input() s = s.upper() dic = {} for i in s: if i == " ": continue if i in dic: dic[i] += 1 else: dic[i] = 1 num = list(dic.values()) no = [] ans = [] for i in range(0,26): t = chr(ord("A")+i) if t not in dic: no.append(t) else: if dic[t] == max(num): ans.append(t) print("出现次数最多的字母是: ",end = "") for i in ans: print(i,end = " ") print("出现次数为:",end = "") print(max(num)) print("未出现的字母是: ",end = "") for i in no: print(i,end = " ")
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0
s=input() a=[0]*26 for i in s: if "A"<=i<="Z": a[ord(i)-ord("A")]+=1 elif "a"<=i<="z": n=ord(i)-ord("a") a[n]=a[n]+1 #找到出现次数最多的字母和未出现的字母 maxn=0;maxi=0;no=[] for i in range(26): if a[i]==0: no.append(chr(ord("A")+i)) elif a[i]>maxn: maxn=a[i] maxi=i for i in range(26): if a[i]==maxn: print(chr(ord("A")+i),end=' ') print() print(maxn) for i in no: print(i,end=' ') #Saying and doing are two different things.
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信息
- ID
- 909
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 8
- 标签
- (无)
- 递交数
- 629
- 已通过
- 120
- 上传者