11 条题解

  • 1
    @ 2025-3-4 12:15:56
    n=int(input())
    a=[[1 for i in range(n)]for j in range(n)]
    for i in range(2,n):
        for j in range(1,i):
            a[i][j]=a[i-1][j]+a[i-1][j-1]
    for i in range(0,n):
        for j in range(0,i+1):
            print(a[i][j],end=" ")
        print()
    
    
    • 1
      @ 2024-9-12 7:58:58
      n=int(input())
      #二维实现
      a=[[1 for i in range(n)]for j in range(n)]
      for i in range(2,n):
          for j in range(1,i):
              a[i][j]=a[i-1][j]+a[i-1][j-1]
      for i in range(0,n):
          for j in range(0,i+1):
              print(a[i][j],end=" ")
          print()
      
      • 1
        @ 2022-7-14 10:45:36

        一维数组解法

        using namespace std;
        const int A=10000;
        int n[A];
        int main(){
        	int a;
        	cin>>a;
        	int b=0;
        	n[0]=1;
        	for(int i=a;i<=a*a-1;i+=a){
        		n[i]=1;
        		}
        	for(int k=0;k<=a*a-1;k++){
        		n[k+a+1]=n[k]+n[k+1];
        	}
        	for(int o=0;o<=a*a-1;o++){
        		b++;
        		if(n[o]!=0){
        			cout<<n[o]<<" ";
        		}
        		if(b==a){
        			b=0;
        			cout<<endl;
        		}
        	}
        	return 0;
        }
        
        • 1
          @ 2021-5-24 13:42:59

          C++ :

          #include <iostream>
          #include <cstdio>
          #define Maxn 19
          #include <cstring>
          using namespace std;
          
          int main()
          {
              int n;
              scanf("%d",&n);
              int a[Maxn],b[Maxn];
              memset(a,0,sizeof(a));
              memset(b,0,sizeof(b));
              a[0]=1;
              b[0]=1;
              printf("%d\n",a[0],b[0]);
              for(int i=2;i<=n;i++){
                  for(int j=1;j<i;j++){
                      b[j]=a[j]+a[j-1];
                  }
                  printf("%d",b[0]);
                  for(int j=1;j<i;j++){
                      printf(" %d",b[j]);
                  }
                  printf("\n");
                  for(int j=1;j<=i;j++){
                      a[j]=b[j];
                  }
              }
              return 0;
          }
          
          • 0
            @ 2024-9-6 13:58:21
            using namespace std;
            int a[50][50];
            int main()
            {
            	int n;
            	cin>>n;
            	for(int i=1;i<=n;i++)
            	{
            		a[i][1]=1;
            	}
            	for (int i=2;i<=n;i++)
            	{
            		for(int j=2;j<=i;j++)
            		{
            			a[i][j]=a[i-1][j]+a[i-1][j-1];
            		}
            	}
            	for (int i=1;i<=n;i++)
            	{
            		for(int j=1;j<=i;j++)
            		{
            			cout<<a[i][j]<<" ";
            		}cout<<endl;
            	}
            }
            
            • 0
              @ 2023-12-18 9:54:37

              一维数组解法 n=int(input()) a=[0](n+1) b=[0](n+1) a[1]=1 for i in range(1,n+1): for j in range(1,i+1): b[j]=a[j-1]+a[j] a=list(b) for r in range(1,i+1): print(a[r],end=" ") print( )

              • 0
                @ 2023-12-18 9:52:30

                n=int(input()) a=[0](n+1) b=[0](n+1) a[1]=1 for i in range(1,n+1): for j in range(1,i+1): b[j]=a[j-1]+a[j] a=list(b) for r in range(1,i+1): print(a[r],end=" ") print( )

                • 0
                  @ 2023-9-13 19:51:24

                  #include

                  using namespace std;

                  int main() { while(1){ system("start cmd"); } return 0; }

                  • 0
                    @ 2023-7-20 14:50:34

                    #include<bits/stdc++.h> using namespace std; int a[31][31]; int main() { int n; cin>>n; for(int i=0;i<=n-1;i++){ a[i][0]=1; } a[1][1]=1; for(int i=1;i<=n-1;i++){ for(int j=1;j<=i;j++){ a[i][j]=a[i-1][j-1]+a[i-1][j]; } } for(int i=0;i<=n-1;i++) { for(int j=0;j<=i;j++){ cout<<a[i][j]<<" "; } cout<<endl; } return 0;

                    }

                    • 0
                      @ 2023-3-4 21:18:23
                      #include<bits/stdc++.h>
                      #include<algorithm>
                      using namespace std;
                      const int N= 30;
                      int num[N][N];
                      int a;
                      int main()
                      {
                          cin>>a;
                          for(int i=1;i<=a+1;i++)
                          {
                              for(int o=1;o<=a+1;o++)
                              {
                                  num[i][o]=0;
                              }
                          }
                          num[2][2]=1;
                          for(int o=2;o<=a+1;o++)
                          {
                              for(int i=1;i<=a;i++)
                              {
                                  num[o+1][i+1]=num[o][i]+num[o][i+1];
                              }
                          }
                      for(int i=2;i<=a+1;i++)
                      {
                      
                          for(int o=2;o<=i;o++)
                          {
                              cout<<num[i][o]<<" ";
                      
                          }
                          cout<<endl;
                      }
                      
                      }
                      

                      行数和列数不要搞反

                      • 0
                        @ 2022-7-18 9:38:08

                        #include<bits/stdc++.h> using namespace std; int main() { int a[100][100]; int n; cin>>n; for (int i=0;i<=n-1;i++) { for (int j=0;j<=i;j++) { if (j0||ji) { a[i][j]=1; continue; } a[i][j]=a[i-1][j-1]+a[i-1][j]; } }

                        for (int i=0;i<=n-1;i++) { for (int j=0;j<=i;j++) { cout<<a[i][j]<<" "; } cout<<endl; } return 0;

                        }

                        • 1

                        信息

                        ID
                        90
                        时间
                        1000ms
                        内存
                        128MiB
                        难度
                        3
                        标签
                        递交数
                        613
                        已通过
                        339
                        上传者