s=""
n=int(input())
i=0
if n==0:
    s="0"
while n>=2**i:
    i=i+1
for j in range(i-1,-1,-1):
    if n>=2**j:
        s=s+"1"
        n-=2**j
    else:
        s=s+"0"
print(s)

n=int(input())
s=""
while n>1:
    t=n%2
    n=n//2;
    s=str(t)+s
s=str(n)+s
print(s)

重做漂泊带土 def f(i): m="" if i!=0: while i>=1: m=m+str(i%2) i=i//2 m=m[::-1] else: m=0 return m i=int(input()) print(f(i))

def dtop(a):
    b = ""
    while a > 0:
        b += str(a%2)
        a = a//2
    b = b[::-1]
    return b
n = int(input())
if n == 0:
    print(0)
else:
    print(dtop(n))

n=int(input())
t=""
if n==0: 
    print(0)
else:
    while n:
        t=str(n%2)+t
        n=n//2
    print(t)

用vector存放答案的时候注意对0进行特判，要不然最后一个测试点过不去

#include <bits/stdc++.h>
using namespace std;

vector<int> ans;

int main()
{
	long long n;
	cin >> n;
	while(n)
	{
		ans.push_back(n%2);
		n/=2;
	}
	for(int i = ans.size()-1;i>=0;i--) cout << ans[i];
	if(ans.empty()) cout << 0;
	return 0;
}

#要求设计自定义函数dtob实现十转二 def dtob(x): s="" while x!=0: y=x%2 s=str(y)+s x=x//2 return s n=int(input()) if n==0: print(0) else:
print(dtob(n))

x=int(input())
s=''
if x==0:
    s=0
while x!=0:
    i=x%2
    x//=2
    s=str(i)+s
print(s)

print(bin(int(input()))[2:])

#include <iostream>
#include<vector>
using namespace std;
int n,ans;
vector<int> a;

int main(){
    cin>>n;
    if(n==1){
        cout<<1;
        exit(0);
    }
    while (n>0){
        ans++;
        a.push_back(n%2);
        n/=2;
    }
    for (int i=ans-1;i>=1;i--)
        cout <<a[i];
    if(n==0){
        cout<<0;
    }
    return 0;
}

c++

#include <bits/stdc++.h>
using namespace std;
int main() {
int a[1000]={0},t=1,j=1;
cin>>a[1];
for(j=1;a[j]>=2;j++)
{
a[j+1]=a[j]/2;
a[j]=a[j]%2;t++;
}
for(int i=t;i>=1;i--)
{
cout<<a[i];
}
return 0;
}

def dtob(x):
    k=0
    s=""
    while x!=0:
        k=1
        s=str(x%2)+s
        x=x//2
    if k==1:
        return s
    else:
        return 0
a=int(input())
print(dtob(a))

print(bin(int(input(),10))[2:])

n=int(input())
t=""
if n==0: 
    print(0)
else:
    while n:
        t=str(n%2)+t
        n=n//2
    print(t)

好东西

a=int(input())
b=""
if a==0:
    print(a)
else:
    while a!=0:
        b=str(a%2)+b
        a=a//2
    print(int(b))