1 条题解
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0
区间乘
#include <bits/stdc++.h> using namespace std; const int N = 100010; int n,m,p; int w[N]; struct SegTree { int l,r;//[l,r] long long sum,add,mul=1;//sum区间查询,add和懒标记,mul积懒标记 }tr[N << 2]; //快读 inline void read(int& x) { x=0;int f = 1;char c = getchar(); while(!isdigit(c)){if(c == '-')f = -1;c = getchar();} while(isdigit(c)){x = (x<<1)+(x<<3)+(c^48);c = getchar();} x*=f; } //向下更新信息 void pushdown(int u) { //根区间,左区间,右区间 SegTree& root = tr[u],& left = tr[u<<1],& right = tr[u<<1|1]; //有懒标记就下放 //左区间的懒标记下放,区间和相当于加上长度*add left.mul=left.mul*root.mul%p; left.add=(left.add*root.mul+root.add)%p; left.sum=((long long)(left.sum*root.mul)+(long long)(left.r-left.l+1)*root.add)%p; //右区间同理 right.mul=right.mul*root.mul%p; right.add=(right.add*root.mul+root.add)%p; right.sum=((long long)(right.sum*root.mul)+(long long)(right.r-right.l+1)*root.add)%p; root.add = 0; root.mul = 1; } //向上更新回根 void pushup(int u) { //左和+右和 tr[u].sum = (tr[u<<1].sum+tr[u<<1|1].sum)%p; } //递归建树tr[u]存储[l,r] void build(int u,int l,int r) { if(l == r) tr[u] = {l,r,w[r],0,1}; else { tr[u] = {l,r}; int mid = (l+r)>>1; //左子树 build(u<<1,l,mid); //右子树 build(u<<1|1,mid+1,r); //递归建树区间和要上传到根 pushup(u); } } //区间修改 void modify(int u,int l,int r,int d) { //在当前区间内部 if(tr[u].l>=l && tr[u].r<=r) { //先把区间更新了,区间和相当于加上长度*add tr[u].sum=(tr[u].sum+(long long)(tr[u].r-tr[u].l+1)*d)%p; //把懒标记更新了 tr[u].add=(tr[u].add+d)%p; } else { //先更新信息,因为要用到子树的性质 pushdown(u); int mid = (tr[u].l+tr[u].r)>>1; //当前区间在左半区间 if(l<=mid) modify(u<<1,l,r,d); //当前区间在右半区间 if(r>mid) modify(u<<1|1,l,r,d); //向上更新 pushup(u); } } void modify1(int u,int l,int r,int d) { if(tr[u].l>=l && tr[u].r<=r) { tr[u].sum=tr[u].sum*d%p; tr[u].add=tr[u].add*d%p; tr[u].mul=tr[u].mul*d%p; } else { pushdown(u); int mid = (tr[u].l+tr[u].r)>>1; if(l<=mid) modify1(u<<1,l,r,d); if(r>mid) modify1(u<<1|1,l,r,d); pushup(u); } } //区间查询 long long query(int u,int l,int r) { //就是当前区间 if(tr[u].l>=l && tr[u].r<=r) return tr[u].sum%p; //向下更新 pushdown(u); int mid = (tr[u].l+tr[u].r) >> 1; long long sum = 0; //当前区间在左半区间 if(l<=mid) sum += query(u<<1,l,r); //当前区间在右半区间 if(r>mid) sum+=query(u<<1|1,l,r); return sum; } int main() { read(n),read(p); for(int i=1;i<=n;i++) read(w[i]); read(m); build(1,1,n); int op,t,g,c; while(m--) { read(op); if(op == 1) { read(t),read(g),read(c); modify1(1,t,g,c); } else if(op == 2) { read(t),read(g),read(c); modify(1,t,g,c); } else { read(t),read(g); printf("%lld\n",query(1,t,g)%p); } } return 0; }
- 1
信息
- ID
- 608
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- 10
- 标签
- 递交数
- 4
- 已通过
- 2
- 上传者