Python的哦~

x=int(input())
i=1
while True:
    i+=1
    if 3**i<=x<3**(i+1):
        print(i)
        break

#include <iostream>
#include<cmath>
using namespace std;
int n;
int main(){
    cin>>n;
    for (int i=0;i<=1000;i++){
        int a=pow(3,i);
        int b=pow(3,i+1);
        if(n>=a&&n<b){
            cout<<i;
            break;
        }
    }
    return 0;
}

c++

包对 #include <bits/stdc++.h> using namespace std; int main() { int n,m=1; cin>>n; for(int i=0;i<=10000;i++){ if(n<m){ cout<<i-1; break; } m=m*3; } return 0; }

#include <bits/stdc++.h>

using namespace std;

int main() { int n,t=3,a=0; cin>>n; while (n>=t) { t*=3; a++; } cout <<a; return 0;

}

#include #include #include using namespace std; int a,c,b; int main() { cin>>a; b=1; while (a>=b) { b*=3; c++; } if (c!=0) { cout<<c-1; } else { cout<<c; } return 0; }

a=int(input())
for i in range(1,a):
    if 3**i<=a and 3**(i+1)>a:
        print(i)
        break

import math n = int(input()) k = int(math.floor(math.log(n, 3))) print(k)

print(int(math.log(int(input()),3)))#最前面加上import math

python

a=int(input())
b=1
flag=True
while flag:
    if 3**b<=a<3**(b+1):
        flag=False
    else:
        b+=1
print(b)

#include <bits/stdc++.h>

using namespace std;
long long n,k=1;
int main()
{
    cin>>n;
    while(pow(3,k)>n || pow(3,k+1)<=n){
        k=k+1;
    }
    cout<<k;
    return 0;
}

a=int(input()) b=0 while b**3<a: b+=1 print(b-1)