n=int(input())

p=[[0 for i1 in range(n)] for i2 in range(n)]

p[0][(n-1)//2]=1

def t(x):

for z in range(n):

for c in range(n):

if p[z][c]==x:

return [z,c]

#t(x)=[x所在行，x所在列]

for k in range(2,n**2+1,1):

j=k-1

if t(j)[0]==0 and t(j)[1]!=n-1:

p[n-1][t(j)[1]+1]=k

elif t(j)[1]==n-1 and t(j)[0]!=0:

p[t(j)[0]-1][0]=k

elif t(j)[0]==0 and t(j)[1]==n-1:

p[1][n-1]=k

else:#if t(j)[0]!=0 and t(j)[1]!=n-1:

if p[t(j)[0]-1][t(j)[1]+1]==0:

p[t(j)[0]-1][t(j)[1]+1]=k

else:

p[t(j)[0]+1][t(j)[1]]=k

for i in p:

op=''

for d in i:

op+=str(d)+' '

print(op)